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BEGIN PRIVACYENHANCED MESSAGE ProcType 01,MICCLEAR OriginatorName webmaster@wwwsecgov OriginatorKeyAsymmetricMar 17, 17 · If a,b,c are in HP then reciprocal of them should be in AP Hence we have the following relation 1/a1/c=2/b =>(ac)/(ac)=2/b(1) =>b(ac)=2ac(2) Now we are to show that a/(bc),b/(ca),c/(ab) are in HP If we can show that the reciprocal of these three are in AP, then the it will be proved that the given three quantities are in HPMATH 215 Homework 1 Solutions In the following problems the sets will be considered in R, not in the set of extended real numbers 1 Let a nonempty subset A ⊂ R be bounded below Light A B C D E F G H And Transmission Electron 1700 I J Download Scientific Diagram ƒuƒƒbƒRƒŠ[ Œ{"÷ ƒŒƒVƒs l‹C ƒNƒbƒNƒpƒbƒh

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